I want to write a script to check out if the website is working fine by checking out some of it is contents. If the content exists in the result, it prints a message telling the website is working fine, otherwise, it will show an error:
#!/bin/bash webserv="10.1.1.1" Keyword="helloworld" # enter the keyword for test content if (curl -s "$webserv" | grep "$keyword") # if the keyword is in the conent echo " the website is working fine" else echo "Error" Any suggestion how to do that?
2 Answers
You're mostly there. Just fix your syntax:
if curl -s "$webserv" | grep "$keyword" then # if the keyword is in the conent echo " the website is working fine" else echo "Error" fi Note the then and fi.
A tiny amend: when setting the variable and using it later, the case needs to match in the two places (ie 'keyword', not 'Keyword'). The full code that works for me:-
#!/bin/bash webserv="10.1.1.1" keyword="helloworld" # enter the keyword for test content if curl -s "$webserv" | grep "$keyword" then # if the keyword is in the content echo " the website is working fine" else echo "Error" fi 
